48771: Discrete Communications- Faculty of Engineering and IT Assessment

January 10, 2018
Author : Alex

Solution Code: 1AFJF

Question: IT Assessment

This assignment falls under “IT Assessment” which was successfully solved by the assignment writing experts at My Assignment Services AU under assignment help through guided sessions service.

IT Assessment

Case Scenario/ Task

solution_1

solution 2

solution 3

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Solution:

Ans Q.No 4

a) Bits required per character : 8 bits , as 27 = 128

b) for 100,000 characters , we will need 7 bits per character, and than 1 bit extra for parity, so total 8 bits *10000 or 8 bits * 23 bit = 186 bits

c) Now for a) we will have 9 bits

and for part b) we will require 9 bits*23 bits = 207 bits

Ans Q 5

Solution

As per Nyquest critera Freq required is 240*2 = 480 Hz

20% extra it makes 480+48+48 = 576 Hz

To take margin for framing +0.5% or add 29Hz , 576 gets raised to 605 Hz

Since we have to transmit 5 signals

Minimum Bandwidth required is = 605*5 = 3025 Hz

Answer-

Q.no6

Solution: given,

            D+1= 12000-200-20200-20220-2

Ans(a): error is shown in red

           D+1= 12000-200-20200-20220-2

Ans(b): sequences that are possible: 1100,1000,0100,1010

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